Say I want to solve this \(\displaystyle\alpha={2}{{\tan}^{{-{1}}}{\left(\sqrt{{{3}-{2}\sqrt{{{2}}}}}\right)}}\)

Rex Maxwell

Rex Maxwell

Answered question

2022-03-31

Say I want to solve this
α=2tan1(322)

Answer & Explanation

glikozyd3s68

glikozyd3s68

Beginner2022-04-01Added 16 answers

α2=arctan322
tanα2=322
tanα2=(21)2
tana2=21
because:
tanα=2tanα21(tanα2)2
tanα=1
as a result:
α=π4

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