Series \(\displaystyle{\sum_{{{k}={1}}}^{{n}}}{\frac{{{\tan{{\frac{{x}}{{{2}^{{k}}}}}}}}}{{{2}^{{{k}-{1}}}{\cos{{\frac{{x}}{{{2}^{{{k}-{1}}}}}}}}}}}\)

Aleah Choi

Aleah Choi

Answered question

2022-03-30

Series k=1ntanx2k2k1cosx2k1

Answer & Explanation

smekkleg5hhp

smekkleg5hhp

Beginner2022-03-31Added 8 answers

Hint:
2cot(2x)=cotxtanx
tanx=2cot(2x)cotx
so
tanx2k2k1cosx2k1=
2cot(2x2k)cotx2k2k1cosx2k1

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