Solving \(\displaystyle{\cos{{x}}}+{\cos{{2}}}{x}-{\cos{{3}}}{x}={1}\) with the substitution \(\displaystyle{z}={\cos{{x}}}+{i}{\sin{{x}}}\)

Rex Maxwell

Rex Maxwell

Answered question

2022-04-02

Solving cosx+cos2xcos3x=1 with the substitution z=cosx+isinx

Answer & Explanation

zalutaloj9a0f

zalutaloj9a0f

Beginner2022-04-03Added 17 answers

There are already some good solutions, but the following solution does use the OP's substitution.
I assume that x is real, then
z=cos(x)+isin(x),z=cos(x)isin(x)=z1
so the equation is equivalent to the following:
z+z1+z2+z2z3z3=2
Let us use the following substitution: q=z+z1,so q2=z2+2+z2 and q3=z3+3z+3z1+z3 ,so the equation is equivalent to the following:
q+q22q3+3q=2
or
q3q24q+4=0
The roots of this cubic equation are integer, so it is easy to find them.

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