Solving \(\displaystyle{\sin{{\frac{{12}}{{x}}}}}=-{3}{\cos{{2}}}{x}\)

smaakt4ucq

smaakt4ucq

Answered question

2022-04-03

Solving sin12x=3cos2x

Answer & Explanation

Mikaela Winters

Mikaela Winters

Beginner2022-04-04Added 14 answers

sin(x2)=1cos(x)2=3cos(2x)
1cos(x)2=9cos2(2x)0=18cos2(2x)+cos(x)1
From here it is a lot of bashing/algebra knowing that cos(2x)=sin2(x)cos2(x)
Alexzander Evans

Alexzander Evans

Beginner2022-04-05Added 9 answers

Let sinx2=a,cosx=12a2
a=3(2(12a2)21)
24a424a2+a+3=0

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