Solving \(\displaystyle{\sin{{3}}}{x}\cdot{\cos{{3}}}{x}={\sin{{2}}}{x}\)

Pasegeabe85xy

Pasegeabe85xy

Answered question

2022-04-03

Solving sin3xcos3x=sin2x

Answer & Explanation

Ben Castillo

Ben Castillo

Beginner2022-04-04Added 13 answers

sin3xcos3x=sin2x
2sin3xcos3x=2sin2x
sin6x=2sin2x
sin3(2x)=2sin2x
3sin2x4sin32x=2sin2x
3sin2x4sin32x2sin2x=0
sin2x4sin32x=0
sin2x(14sin22x)=0
Then
sin2x=0
and
sin2x=±12

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