Solving \(\displaystyle{2}{\sin{{x}}}{\left(\sqrt{{3}}{\cos{{x}}}-{\sin{{x}}}\right)}=\sqrt{{2}}-{1}\) I have gone this far: \(\displaystyle{4}{\sin{{x}}}{\sin{{\left({60}^{{\circ}}-{x}\right)}}}=\sqrt{{{2}}}-{1}\)

Rolando Wade

Rolando Wade

Answered question

2022-04-01

Solving 2sinx(3cosxsinx)=21
I have gone this far:
4sinxsin(60x)=21

Answer & Explanation

Abdullah Avery

Abdullah Avery

Beginner2022-04-02Added 19 answers

Hint:
23sinxcosx2sin2x=3sin2x+cos2x1=21
Then
3sin22x=3(1cos22x)=(2cos2x)2
This is a quadratic equation in cos2x

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