Solving \(\displaystyle{2}{{\sin}^{{2}}{x}}+{6}{{\sin}^{{2}}{\frac{{12}}{{x}}}}={3}\) Find the angles between \(\displaystyle{0}^{{\circ}}\

ideklaraz7xz

ideklaraz7xz

Answered question

2022-04-02

Solving 2sin2x+6sin212x=3
Find the angles between 0  and  360 which satisfy the equation above.
So, I found the answers by inputting all the possible special angles; 60  and  120 worked.
Are there any other ways to find the answers, and are there more than the two answers that I found?

Answer & Explanation

SofZookywookeoybd

SofZookywookeoybd

Beginner2022-04-03Added 15 answers

HINT
Recall that
sin2x2=1212cosx
sin2x=1cos2x
therefore
2sin2x+6sin2x2=322cos2x+33cosx=32cos2x+3cosx2=0

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