Solving \(\displaystyle{2}{\cos{{2}}}{x}-{4}{\sin{{x}}}{\cos{{x}}}=\sqrt{{{6}}}\)

Hanzikoval1pa

Hanzikoval1pa

Answered question

2022-04-02

Solving 2cos2x4sinxcosx=6

Answer & Explanation

kachnaemra

kachnaemra

Beginner2022-04-03Added 16 answers

Note that
2cos(2x)2sin(2x)=22+22cos(2x+α)
where
cosα=sinα=222=12
Hence, you'll have
22cos(2x+45)=6cos(2x+45)=622=32
Ariel Cantrell

Ariel Cantrell

Beginner2022-04-04Added 8 answers

2cos2x2(2sinxcosx)=6
2cos2x2sin2x=6
R=8=22
α=arctan22=π4
cos(2xπ4)=32

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