Solving the equation: \(\displaystyle{3}{\cos{{x}}}-{\sin{{2}}}{x}=\sqrt{{{3}}}{\left({\cos{{2}}}{x}+{\sin{{x}}}\right)}\)

Marzadri9lyy

Marzadri9lyy

Answered question

2022-04-03

Solving the equation:
3cosxsin2x=3(cos2x+sinx)

Answer & Explanation

clarkchica44klt

clarkchica44klt

Beginner2022-04-04Added 17 answers

After staring at this for a while I think I've got it. Assuming what you've done so far is correct
sin(π3+2x)=sin[π(π3+2x)]=sin(2π32x)
Substituting this gives
3sin(π3x)=sin(2π32x)
3sin(π3x)=2sin(π3x)cos(π3x)
sin(π3x)[32cos(π3x)]=0

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?