Solving trigonometry equation \(\displaystyle{3}{{\sin}^{{2}}{x}}-{3}{{\cos}^{{2}}{x}}+{\cos{{x}}}-{1}={0}\)

Polchinio3es

Polchinio3es

Answered question

2022-04-03

Solving trigonometry equation
3sin2x3cos2x+cosx1=0

Answer & Explanation

Dixie Reed

Dixie Reed

Beginner2022-04-04Added 15 answers

3sin2x3cos2x+cosx1=0
6cos2xcosx2=0
By the quadratic formula
cosx=1±14(6)(2)12=1±712
So cosx=12 and cosx=23

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