Equivalent of \(\displaystyle\frac{{\sin{{\left({x}\right)}}}}{{x}}={\sin{{c}}}{\left({x}\right)}\) for \(\displaystyle\frac{{{\cos{{\left({x}\right)}}}-{1}}}{{x}}\)

Rolando Wade

Rolando Wade

Answered question

2022-04-03

Equivalent of sin(x)x=sinc(x) for cos(x)1x

Answer & Explanation

Laylah Hebert

Laylah Hebert

Beginner2022-04-04Added 15 answers

1cosx=2sin2(x2)
cosx1x=2sin2(x2)x=2 sinc2(x2)x(x2)2=x2sinc2(x2)
or also cosx1x=sinc(x2)sin(x2)

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