Evaluate \(\displaystyle{\int_{{-\frac{{1}}{\sqrt{{{3}}}}}}^{{\frac{{1}}{\sqrt{{{3}}}}}}}{\frac{{{x}^{{4}}}}{{{1}-{x}^{{4}}}}}{{\cos}^{{-{1}}}{\frac{{{2}{x}}}{{{1}+{x}^{{2}}}}}}{\left.{d}{x}\right.}\)

nomadzkia0re

nomadzkia0re

Answered question

2022-04-05

Evaluate
1313x41x4cos12x1+x2dx

Answer & Explanation

horieblersee275

horieblersee275

Beginner2022-04-06Added 17 answers

A=cos12x1+x2
Now t=x or x=t
A=arccos2t1+(t)2=arccos(2t1+t2)
Now:
arccos(x)=πarccos(x)
So
A=πarccos2t1+t2
And:
I=1313x41x4cos12x1+x2dx
I=1313x41x4(πcos12x1+x2)dx
Adding:
2I=1313(cos12x1+x2+πcos12x1+x2)dx
2I=1313x41x4(π)dx

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