Evaluate \(\displaystyle{\sum_{{{n}={1}}}^{{{38}}}}{\sin{{\left({\frac{{{n}^{{8}}\pi}}{{{38}}}}\right)}}}\)

Pizzadililehz

Pizzadililehz

Answered question

2022-04-03

Evaluate
n=138sin(n8π38)

Answer & Explanation

disolutoxz61

disolutoxz61

Beginner2022-04-04Added 12 answers

We have:
n=138sin(n8π38)=k=018sin((2k+1)82π419)+k=018sin(26k82π19)
where the first sum vanishes because -2 is a fourth power (mod19), since 54+20(mod19), while the second sum is just the imaginary part of a Gauss sum:
k=018sin(26k82π19)=Im=018(mq)exp(72πim19)=19
because the eighth powers (mod19) are just the quadratic residues.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?