Evaluate \(\displaystyle{{\tan{{20}}}^{\circ}+}{{\tan{{40}}}^{\circ}+}\sqrt{{{3}}}{{\tan{{20}}}^{\circ}{{\tan{{40}}}^{\circ}}}\)

Caerswso1pc

Caerswso1pc

Answered question

2022-04-04

Evaluate
tan20+tan40+3tan20tan40

Answer & Explanation

alwadau8ndv

alwadau8ndv

Beginner2022-04-05Added 9 answers

One has
tan(α+β)=tanα+tanβ1tanαtanβ
One then has
3=tan60=tan(20+40)=tan20+tan401tan20tan40
tan20+tan40+3tan20tan40=3.

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