Evaluate without using a calculator: \(\displaystyle{\tan{{\left({2}{{\sin}^{{-{1}}}{\left({\frac{{\sqrt{{{5}}}}}{{{5}}}}\right)}}\right)}}}\)

Marzadri9lyy

Marzadri9lyy

Answered question

2022-04-05

Evaluate without using a calculator:
tan(2sin1(55))

Answer & Explanation

Carter Lin

Carter Lin

Beginner2022-04-06Added 13 answers

Let sin155=θ
(i)sinθ=55=15
and (ii)π2θ<π2 based on the definition of principal value
In fact, 0<θ<π2
cosθ=+1sin2θ=+25
So, tan(2sin155)=tan2θ=sin2θcos2θ=2sinθcosθ2cos2θ1

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