Express \(\displaystyle{6}\theta\) in terms of \(\displaystyle{\cos{\theta}}\)

Tony Mccarthy

Tony Mccarthy

Answered question

2022-04-03

Express 6θ in terms of cosθ

Answer & Explanation

Jared Kemp

Jared Kemp

Beginner2022-04-04Added 14 answers

Since
cos2a=2cos2a1, sin2a=2sinacosa
cos(a+b)=cosacosbsinasinb
and
cos3θ=cos(2θ+θ)
=cos2θcosθsin2θsinθ
=(2cos2θ1)cosθ2sin2θcosθ
=(2cos2θ1)cosθ2(1cos2θ)cosθ
=4cos3θ3cosθ
we have
cos6θ=cos(2×3θ)
=2cos23θ1
=2(4cos3θ3cosθ)21
=32cos6θ48cos4θ+18cos2θ1

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