Find the value of the following series. \(\displaystyle{\tan{\theta}}+{2}{\tan{{\left({2}\theta\right)}}}+{2}^{{2}}{\tan{{\left({2}^{{2}}\theta\right)}}}+\cdots+{2}^{{{14}}}{\tan{{\left({2}^{{{14}}}\theta\right)}}}+{2}^{{{15}}}{\cot{{\left({2}^{{{15}}}\theta\right)}}}\)

delitzo1d4

delitzo1d4

Answered question

2022-04-07

Find the value of the following series.
tanθ+2tan(2θ)+22tan(22θ)++214tan(214θ)+215cot(215θ)

Answer & Explanation

cinereod3am

cinereod3am

Beginner2022-04-08Added 10 answers

cotxtanx=dcos2xsin2xsinxcosx=2cot2x
Set x=θ,2θ,22θ,.2nθ where n is a non-negative integer
cotθtanθ=2cot2θ
2(cot2θtan2θ)=2(2cot22θ)
22(cot22θtan22θ)=22(2cot23θ)
2n(cot2nθtan2nθ)=2n(2cot2n+1θ)
Adding we get
cotθr=1n2rtan2rθ=2n+1cot2n+1θ
r=1n2rtan2rθ=cotθ2n+1cot2n+1θ

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