How to prove \(\displaystyle{\frac{{{1}+{\tan{{x}}}}}{{{1}-{\tan{{x}}}}}}={\frac{{{{\sec}^{{2}}{x}}+{2}{\tan{{x}}}}}{{{2}-{{\sec}^{{2}}{x}}}}}\)

Mary Bates

Mary Bates

Answered question

2022-04-07

How to prove 1+tanx1tanx=sec2x+2tanx2sec2x

Answer & Explanation

Kapovkah7hpl

Kapovkah7hpl

Beginner2022-04-08Added 14 answers

sec2x+2tanx2sec2x=1+tan2x+2tanx2(1+tan2x)
=1+2tanx+tan2x1tan2x
=(1+tanx)2(1+tanx)(1tanx)
=1+tanx1tanx

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?