How to prove that \(\displaystyle\frac{{1}}{{{\sin}^{{2}}{x}}}+\frac{{1}}{{{\sin}^{{2}}{y}}}-{\frac{{{2}{\cos{{\left({x}-{y}\right)}}}}}{{{\left({\sin{{x}}}{\sin{{y}}}\right)}}}}=\frac{{{\sin}^{{2}}{\left({x}-{y}\right)}}}{{{{\sin}^{{2}}{x}}{{\sin}^{{2}}{y}}}}\)

Kasey Castillo

Kasey Castillo

Answered question

2022-04-06

How to prove that 1sin2x+1sin2y2cos(xy)(sinxsiny)=sin2(xy)sin2xsin2y

Answer & Explanation

anita1415snck

anita1415snck

Beginner2022-04-07Added 19 answers

The numerator
=sin2x+sin2ycos(xy)2sinxsiny
=sin2x+sin2ycos(xy)[cos(xy)cos(x+y)]
=sin2x+sin2ycos2(xy)+cos(xy)cos(x+y)
Now use Prove that cos(A+B)cos(AB)={cos2}A{sin2}B

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