I was evaluating the range of this function

Quinn Moses

Quinn Moses

Answered question

2022-04-08

I was evaluating the range of this function in real numbers:
f(x)=(x+x)(10x+10x)

Answer & Explanation

cutimnm135imsa

cutimnm135imsa

Beginner2022-04-09Added 21 answers

See that the domain of f(x) is [xxR+ 0x10] and that
f(x)=(1+12x)(10x+10x)(x+x)(1+1210x)
=10x+10x+12x(10x+10x)xxx+x210x
If you solve for f(x)=0, you will get x=5 and f(5)<0.

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