I wonder how to solve this equation: \(\displaystyle{\frac{{{\tan{{\left({x}+{20}^{\circ}\right)}}}-{\sin{{\left({x}+{20}^{\circ}\right)}}}}}{{{\tan{{\left({x}+{20}^{\circ}\right)}}}+{\sin{{\left({x}+{20}^{\circ}\right)}}}}}}\)

Mina Whitehead

Mina Whitehead

Answered question

2022-04-06

I wonder how to solve this equation:
tan(x+20)sin(x+20)tan(x+20)+sin(x+20)

Answer & Explanation

phoenixtreeaung

phoenixtreeaung

Beginner2022-04-07Added 19 answers

tan(x+20)sin(x+20)tan(x+20)+sin(x+20)
=sin(x+20)cos(x+20)sin(x+20)sin(x+20)cos(x+20)+sin(x+20)
=sin(x+20)1cos(x+20)1sin(x+20)1cos(x+20)+1
=sin(x+20)cos(x+20)1cos(x+20)sin(x+20)cos(x+20)1+cos(x+20)
=tan(x+20)2sin2(x2+10)tan(x+20)2cos2(x2+10)
=tan(x+20)tan(x+20)tan2(x2+10)
Thus you can rewrite
tan(x+20)sin(x+20)tan(x+20)+sin(x+20)=4sin2(x2+10)
as
tan(x+20)tan(x+20)tan2(x2+10)=4sin2(x2+10)
tan(x+20)tan(x+20)1cos2(x2+10)=4cos2(x2+10)
tan(x+20)cos2(x2+10)=4tan(x+20)cos2(x2+10)
3tan(x+20)cos2(x2+10)=0
tan(x+20)=0
x+20=0
x=20+kπ kZ

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