I'm trying to calculate below integral but I'm

Essence Ingram

Essence Ingram

Answered question

2022-04-06

I'm trying to calculate below integral but I'm not able to do so:
1202cos(2π60t)dt=1202cos(2π60t)dt

Answer & Explanation

cadhail6n1t

cadhail6n1t

Beginner2022-04-07Added 14 answers

π is just another constant. Find that sin(ax)=acos(ax) by the chain rule. This gives you
cos(ax)dx=1asin(ax)
So in particular
cos(2π60t)dt=1120πsin(120πt)+C
As you noted correctly, the period of this function is 160 so the definite integral would be
1120π(sin2πsin0)=0
NB that you made a mistake: cos2xdx=12sin2x, note the argument of sin is 2x and not x.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?