trigonometric transformation \(\displaystyle{\frac{{{\left({\cos{{x}}}+{i}{\sin{{x}}}\right)}-{1}}}{{{\left({\cos{{x}}}+{i}{\sin{{x}}}\right)}+{1}}}}=-{i}{\tan{{\left(\frac{{x}}{{2}}\right)}}}\)

Jayleen Aguirre

Jayleen Aguirre

Answered question

2022-04-10

trigonometric transformation (cosx+isinx)1(cosx+isinx)+1=itan(x2)

Answer & Explanation

o2z1zsjj0

o2z1zsjj0

Beginner2022-04-11Added 10 answers

1(cosx+isinx)1+(cosx+isinx)=
1cosxisinx1+cosx+isinx=
2sin2(x2)i2sin(x2)cos(x2)2cos2(x2)+i2sin(x2)cos(x2)=
simplify
=sin(x2)cos(x2)sin(x2)icos(x2)cos(x2)+isin(x2)=
tan(x2)×ii×sin(x2)icos(x2)cos(x2)+isin(x2)=
1itan(x2)isin(x2)-i2cos(x2)cos(x2)+isin(x2)=
1itan(x2)isin(x2)+cos(x2)cos(x2)+isin(x2)=
1itan(x2)=
itan(x2)

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