Trigonometry Identity: \(\displaystyle{3}{\left({{\cot}^{{2}}\theta}+{1}\right)}-{{\csc}^{{2}}\theta}-{1}={{\cot}^{{2}}\theta}+{{\csc}^{{2}}\theta}\)

zdebe5l8

zdebe5l8

Answered question

2022-04-08

Trigonometry Identity:
3(cot2θ+1)csc2θ1=cot2θ+csc2θ

Answer & Explanation

Alonso Christian

Alonso Christian

Beginner2022-04-09Added 11 answers

You mention converting the cot to csc presumably via the identity cot2+1=csc2 but perhaps you got off track.
3(cot2θ+1)csc2θ1=3csc2θcsc2θ1
=2csc2θ1
=csc2θ+(csc2θ1)
=csc2θ+cot2θ
tempur8x43

tempur8x43

Beginner2022-04-10Added 16 answers

Lets, not make extra work for yourself. You already have a cot2θ, so keep it.
3(cot2θ+1)csc2θ1=(cot2θ+1)+2(cot2θ+1)csc2θ1
=cot2θ+2(cot2θ+1)csc2θ
=cot2θ+2csc2θcsc2θ
=cot2θ+csc2θ

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