Understanding equality \(\displaystyle{\frac{{{1}}}{{{2}}}}{\int_{{0}}^{{{2}\pi}}}{\frac{{{\cos{{\left(\theta\right)}}}}}{{{2}+{\cos{{\left(\theta\right)}}}}}}{d}\theta=\pi-{\int_{{0}}^{{{2}\pi}}}{\frac{{{d}\theta}}{{{2}+{\cos{{\left(\theta\right)}}}}}}\)

Breanna Fisher

Breanna Fisher

Answered question

2022-04-11

Understanding equality 1202πcos(θ)2+cos(θ)dθ=π02πdθ2+cos(θ)

Answer & Explanation

izvozna39g0

izvozna39g0

Beginner2022-04-12Added 9 answers

We have
1202πcos(θ)2+cos(θ)dθ=1202πcos(θ)+222+cos(θ)dθ=12(02πdθ02π2dθ2+cos(θ))

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