Vanessa Mccarty
2022-04-13
ktetik7aeg
Beginner2022-04-14Added 10 answers
, so our expression is
for . Since , we are requesting potential quadratic values for y in that range. So, merely think about the related parabola, let's say , in the yz-plane.
I am aware that it is upside-down and that the axis of symmetry is at y=1/4.
Then test the boundary values to find a minimum value z=-2 at y=-1. By continuity (i.e. the intermediate value theorem) the range is
Mdladlaqe2t
Beginner2022-04-15Added 7 answers
Make use of the double-angle formula multiply by -8 and complete the square. We have
The LHS's minimum value is 0 and its maximum value is for m & the LHS has a maximum value of 25 giving an lower bound of -2 for m. So
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