Find the derivative: \(\displaystyle{y}={\arcsin{{\left({2}{x}+{1}\right)}}}\)

Jazmin Strong

Jazmin Strong

Answered question

2022-04-14

Find the derivative:
y=arcsin(2x+1)

Answer & Explanation

szalbierzfytg

szalbierzfytg

Beginner2022-04-15Added 13 answers

Apply the chain rule:
y=dgdududx
with g=arcsin(u) and u=2x+1
g=11u2
u=2
My solution therefore was
11u22=21(2x+1)2
21(2x+1)2=21(4x2+4x+1)
=24x24x
=24(x2x)
=24x2x
=1x2x

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