How do I prove that \(\displaystyle{\frac{{{\sin{{\left(\alpha-\beta\right)}}}}}{{{\sin{\alpha}}-{\sin{\beta}}}}}={\frac{{{\sin{\alpha}}+{\sin{\beta}}}}{{{\sin{{\left(\alpha+\beta\right)}}}}}}\) Using double

Joaquin Salas

Joaquin Salas

Answered question

2022-04-15

How do I prove that sin(αβ)sinαsinβ=sinα+sinβsin(α+β)
Using double angle and addition formulas, I simplified the LHS to cosαβ2cosα+β2

Answer & Explanation

star04iks7

star04iks7

Beginner2022-04-16Added 14 answers

Method#1:
Use Prosthaphaeresis Formulas and double angle formula:
sin2x=2sinxcosx
in the Right Hand Side as well.
Method#2:
Alternatively using Prove sin(A+B)sin(AB)=sin2Asin2B
sin(A+B)sin(AB)=sin2Asin2B=?
glanzerjbdo

glanzerjbdo

Beginner2022-04-17Added 13 answers

sin(αβ)sinαsinβ=sin(αβ)sin(α+β)(sinαsinβ)(sin(α+β))
Recall that sin(αβ)sin(α+β)=sin2αsin2β
Simplifying, we get:
sinα+sinβsin(α+β) =RHS
Q.E.D.

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