knowing: \(\displaystyle{\tan{{x}}}={2}-\sqrt{{3}}\), obtain: \(\displaystyle{\cos{{2}}}{x}\) I tried converting

Aliana Alvarez

Aliana Alvarez

Answered question

2022-04-16

knowing: tanx=23, obtain: cos2x
I tried converting tanx into it's sinus and cosine form and trying to square both sides to try to get the form of:
cos2xsin2x
But I can't really get to this form without having extra expressions of sine or cosine, any ideas how to start this properly?
Taken out of one of the entry tests to Maths in TAU.
Solution:
cos2x=cos2xsin2x=cos2xsin2xsin2x+cos2x:cos2xcos2x=1tan2x1+tan2x
1tan2x1+tan2x=6+43843=3+23423

Answer & Explanation

cm1mmeboulbes21e1

cm1mmeboulbes21e1

Beginner2022-04-17Added 8 answers

One may use the following identities:
cos2(x)=11+tan2(x)
cos(2x)=2cos2(x)1
legaldaj1dn

legaldaj1dn

Beginner2022-04-18Added 9 answers

HINT
Recall that by half-angle identities
cos2x=1tan2x1+tan2x

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