How do I show that \(\displaystyle{\frac{{{1}}}{{{\left({1}-{\cos{{\left\lbrace\theta\right\rbrace}}}\right)}^{{2}}}}}={\frac{{14}}{{\csc}}}^{{4}}{\left\lbrace{\frac{{{1}}}{{{2}}}}\right\rbrace}\theta\) I've tried

Bryanna Leon

Bryanna Leon

Answered question

2022-04-15

How do I show that 1(1cos{θ})2=14csc4{12}θ
I've tried fiddling around with half angle formulae but can't get the required result.

Answer & Explanation

glajusv8iv

glajusv8iv

Beginner2022-04-16Added 10 answers

Try to use this relation :
1cosθ=2sin2(θ2)
gigglesbuggk1co

gigglesbuggk1co

Beginner2022-04-17Added 13 answers

As stated in comments and answers:
cos(2α)12sin2(α)
[This identity can be derived from the addition formula cos(α+β)cosαcosβsinαsinβ, using β=α]
This leads to
1cos(2α)=2sin2(α)
In your case: 2α=θα=θ2
And so:
1(1cosθ)2=1(2sin2θ2)2=14sin4θ2

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