How do i solve \(\displaystyle{\sin{{\left({8}{x}\right)}}}-{\cos{{\left({6}{x}\right)}}}=\sqrt{{{3}}}{\left({\sin{{\left({6}{x}\right)}}}+{\sin{{\left({8}{x}\right)}}}\right)}\)

Alivia Rojas

Alivia Rojas

Answered question

2022-04-18

How do i solve
sin(8x)cos(6x)=3(sin(6x)+sin(8x))

Answer & Explanation

tabuevniru8op

tabuevniru8op

Beginner2022-04-19Added 14 answers

Should it be
sin(8x)cos(6x)=3(sin(6x)+cos(8x))
sin8x3cos8x=3sin6x+cos6x
sin(8xπ3)=sin(6x+π6)
Now siny=sinAy=nπ+(1)nA where n is any integer

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