How do you establish the trigonometric identity? \(\displaystyle{\frac{{{\left({2}{{\cos}^{{2}}\theta}-{1}\right)}^{{2}}}}{{{{\cos}^{{4}}\theta}-{{\sin}^{{4}}\theta}}}}={1}-{2}{{\sin}^{{2}}\theta}\)

Haylee Bowen

Haylee Bowen

Answered question

2022-04-17

How do you establish the trigonometric identity?
(2cos2θ1)2cos4θsin4θ=12sin2θ

Answer & Explanation

firyemv3

firyemv3

Beginner2022-04-18Added 10 answers

(2cos2θ1)2cos4θsin4θ
Since (2cos2θ1)2=(cos2θ)2 This becomes:
(cos(2θ))2(cos2θ)2(sin2θ)2
This implies:
(cos(2θ))2(cos2θ+sin2θ)(sin2θcos2θ)
Now we know that (cos2θsin2θ)=cos(2θ) This becomes
(cos(2θ))2cos2θ
=cos2θ=12sin2θ
tabuevniru8op

tabuevniru8op

Beginner2022-04-19Added 14 answers

We can show this using the fact that sin2x+cos2x=1 and algebraic manipulation like so:
(2cos2x1)2cos4xsin4x=(cos2x+cos2x1)2(cos2xsin2x)(cos2x+sin2x)
=(cos2xsin2x)2(cos2xsin2x)(cos2x+sin2x)
=cos2xsin2x
=cos2xsin2x+sin2xsin2x
=12sin2x

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