Solve \cos x<\frac{\sqrt{3}}{2},\ x\in[0,2\pi]

yopopolin10d

yopopolin10d

Answered question

2022-04-22

Solve
cosx<32, x[0,2π]

Answer & Explanation

Zemmiq34

Zemmiq34

Beginner2022-04-23Added 11 answers

Actually I found
π6<x<11π6
so
x[π6,11π6]
The set of solution you found
S=[0,2π][π6,11π6]
is the answer to the inequality
cosx>32, x[0,2π]

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