Solve: 2+\cos\frac{3x}{2}+\sqrt{3}\sin\frac{3x}{2}=4\sin^2\frac{x}{4}

Wissety52

Wissety52

Answered question

2022-04-21

Solve:
2+cos3x2+3sin3x2=4sin2x4

Answer & Explanation

Cynthia Herrera

Cynthia Herrera

Beginner2022-04-22Added 16 answers

We have
2+cos3x2+3sin3x2=4sin2x4
1+12cos3x2+32sin3x2=42sin2x4
cos3x2cosπ3+sin3x2sinπ3=(12sin2x4)
cos3x2π3)=cosx2=cos(πx2)
Now, writing the general solution as follows
3x2π3=2nπ±(πx2)
taking positive sign, we get
3x2π3=2nπ±(πx2)
2x=2nπ+4π3
x=nπ+2π3
taking negative sign, we get
3x2π3=2nπ(πx2)
x=2nππ+π3
x=2nπ2π3
where, n is any integer.

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