Solving a cubic equation involving trigonometric functions \sin(x)-\cos(x)=\frac{\sqrt{3}}{2} then \sin^3(x)-\cos^3(x)=?

dreangannaa

dreangannaa

Answered question

2022-04-20

Solving a cubic equation involving trigonometric functions
sin(x)cos(x)=32
then
sin3(x)cos3(x)=?

Answer & Explanation

Celia Morse

Celia Morse

Beginner2022-04-21Added 11 answers

sin(x)cos(x)=32
sin2(x)+cos2(x)2sinxcosx=34
sinxcosx=18
(using sin2x+cos2x=1)
Now using a3b3=(ab)(a2+ab+b2)
sin3(x)cos3x(sinxcosx)(sin2x+cos2x+sinxcosx)
=32×(1+18)
=9316

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