Variation of x\to \tan x over (\pi/2,\pi ] without using

Ari Sheppard

Ari Sheppard

Answered question

2022-04-20

Variation of xtanx over (π2,π] without using derivation?

Answer & Explanation

Cristal Roth

Cristal Roth

Beginner2022-04-21Added 13 answers

Note that
sinx>0sinx1<sinx2sinx1sinx2<1
cosx<0cosx1<cosx2cosx2cosx1<1
then since tanx<0
sinx1sinx2cosx2cosx1=tanx1tanx2<1tanx1>tanx2

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