How prove that sum \frac{1}{\sin^2\frac{\pi}{2n}}+\frac{1}{\sin^2\frac{2\pi}{2n}}+\cdots+\frac{1}{\sin^2\frac{(n-1)\pi}{2n}} =\frac{2}{3}(n-1)(n+1)

Angeline Hayden

Angeline Hayden

Answered question

2022-04-23

How prove that sum
1sin2π2n+1sin22π2n++1sin2(n1)π2n=23(n1)(n+1)

Answer & Explanation

Kendrick Fritz

Kendrick Fritz

Beginner2022-04-24Added 12 answers

So:
k=1n11sin2(kπn)=(n1)(n+1)3
All you have to do now, is show that:
k=1n11sin2(kπ2n)=2k=1n11sin2(kπn)

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