How to evaluate \int\frac{\sin^3x}{\cos^5x}dx

Sydney Stanley

Sydney Stanley

Answered question

2022-04-22

How to evaluate
sin3xcos5xdx

Answer & Explanation

Brennen Davies

Brennen Davies

Beginner2022-04-23Added 25 answers

Another approach:
sin3xcos5xdx=sin3xcos3xcos2xdx
=(sinxcosx)3dxcos2x
=tan3xd(tanx)
=14tan4x+C
Assainato9gf

Assainato9gf

Beginner2022-04-24Added 15 answers

Let u=cosx then du=sinxdx so
sin3xcos5xdx=1u2u5du
=u44u22+C
=cos4x4cos2x2+C

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