How to evaluate \int \frac{1+\cos 2x}{\sin^2 2x}

hapantad2j

hapantad2j

Answered question

2022-04-23

How to evaluate 1+cos2xsin22x

Answer & Explanation

Kendrick Fritz

Kendrick Fritz

Beginner2022-04-24Added 12 answers

cos(2x)+1sin2(2x)dx=csc2(x)2dx=
=12csc2t(x)dx=
=cot(x)2+C
Luke Kane

Luke Kane

Beginner2022-04-25Added 14 answers

Again here is the problem
cot(u)sin(u)du=csc(u)cot(u)du=csc(u)
So final solution according to your method is :
12(cot(2x)+csc(2x))+c

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