If a,b,c are in an Arithmetic Progression (AP), prove that \frac{\sin{c}-\sin{a}}{\cos{a}-\cos{c}}=\cot{b}

spetterde52g

spetterde52g

Answered question

2022-04-20

If a,b,c are in an Arithmetic Progression (AP), prove that
sin{c}sin{a}cos{a}cos{c}=cot{b}

Answer & Explanation

Alexis Wolf

Alexis Wolf

Beginner2022-04-21Added 13 answers

The trick is let
a=A-d
b=A
and
c=A+d
sin{c}sin{a}cos{a}cos{c}=sin{(A+d)}sin{(Ad)}cos{(Ad)}cos{(A+d)}
sin{A}cos{d}cos{A}sin{d}sin{A}cos{d}cos{A}sin{d}cos{A}cos{d}sin{A}sin{d}cos{A}cos{d}sin{A}sin{d}
Which simplifies to
cos{A}sin{A}
cos{A}sin{A}=cot{A}
cot{A}=cot{b}
morpheus1ls1

morpheus1ls1

Beginner2022-04-22Added 22 answers

Since a+c2=b, for d2πk, where kZ and sinb0 we obtain
sin{c}sin{a}cos{a}cos{c}=2sinca2cosa+c22sinca2sina+c2=cot{b}

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