if a\cos\theta-b\sin\theta=c Prove that a\cos\theta -b\sin\theta =\pm\root()(a^{2}+b^{2}-c^{2})

Elise Winters

Elise Winters

Answered question

2022-04-23

if acosθbsinθ=c
Prove that acosθbsinθ=±a2+b2c2()

Answer & Explanation

Brenton Steele

Brenton Steele

Beginner2022-04-24Added 18 answers

Step 1
Given
acosθbsinθ=c
Step 2
We have
(acosθbsinθ)2+(asinθbcosθ)2
=(a2cos2θ+b2sin2θ2absinθcosθ)+(a2sin2θ+b2cos2θ2absinθcosθ)
=a2(cos2θ+sin2θ)+b2(sin2θ+cos2θ)
=a2+b2[sin2θ+cos2θ=1]
c2=(asinθ+bcosθ)2=a2+b2
(asinθ+bcosθ)2=a2+b2c2
asinθ+bcosθ=±a2+b2c2()
asinθ+bcosθ=±a2+b2c2()

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