Implict differentiation: x\cos(4x+3y)=y\sin x

redupticslaz

redupticslaz

Answered question

2022-04-22

Implict differentiation:
xcos(4x+3y)=ysinx

Answer & Explanation

Patricia Duffy

Patricia Duffy

Beginner2022-04-23Added 16 answers

sin(4x+3y)+xcos(4x+3y)(4+3dydx)=(dydx)cosxysinx
sin(4x+3y)+4xcos(4x+3y)+3(dydx)cos(4x+3y)=(dydx)cosxysinx
sin(4x+3y)+4xcos(4x+3y)+ysinx=(dydx)cosx+3(dydx)cos(4x+3y)
sin(4x+3y)+4xcos(4x+3y)+ysinx=(dydx)(cosx+3cos(4x+3y))

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