Integrate the function \frac{2x^3+5x^2+8x+4}{(x^2+2x+2)^2}

topoit8d

topoit8d

Answered question

2022-04-24

Integrate the function
2x3+5x2+8x+4(x2+2x+2)2

Answer & Explanation

alastrimsmnr

alastrimsmnr

Beginner2022-04-25Added 18 answers

Let us start with
2x3+5x2+8x+4(x2+2x+2)2=A+Bxx2+2x+2+C+Dx(x2+2x+2)2
Remove the denominator, expand and group the terms. You should arrive to
2x3+5x2+8x+4=Bx3+(A+2B)x2+(2A+2B+D)x+(2A+C)
which gives the four equations B=2, A+2B=5 so A=1, 2A+2B+D=8 so D=2, 2A+C=4 so C=2
So we have
2x3+5x2+8x+4(x2+2x+2)2=1+2xx2+2x+2+2+2x(x2+2x+2)2
=2x+21x2+2x+2+2x+2(x2+2x+2)2
So, setting u=x2+2x+2, you can notice that 2x+2 is just u' which make things very simple for two parts and what is basically left is
dxx2+2x+2=dx(x+1)2+1
I am sure that you can take from here.

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