Simplifying \frac{\sin40^{\circ}-\sqrt{3}\cos40^{\circ}}{\sin10^{\circ}\cos10^{\circ}}

Ezequiel Olson

Ezequiel Olson

Answered question

2022-04-26

Simplifying sin403cos40sin10cos10

Answer & Explanation

Jayla Matthews

Jayla Matthews

Beginner2022-04-27Added 18 answers

B=sin(40)3cos(40)sin(10)cos(10)
=2(12sin(40)32cos(40))sin(10)cos(10)
=2(sin(30)sin(40)cos(30)cos(40))sin(10)cos(10)
=2cos(70)sin(10)cos(10)
=4cos(70)sin(20)
Now, remember that cos(90x)=sin(x)
=-4
foireatoutmtw

foireatoutmtw

Beginner2022-04-28Added 15 answers

One has
B=2sin40sin30cos40cos30sin10cos10=2cos(40+30)sin10cos10=2sin20sin10cos10=4

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