Show that the equation below is only possible when x=y \sec^2\theta=\frac{4xy}{(x+y)^2}

tefoldaavv

tefoldaavv

Answered question

2022-05-01

Show that the equation below is only possible when x=y
sec2θ=4xy(x+y)2

Answer & Explanation

amisayq6t

amisayq6t

Beginner2022-05-02Added 18 answers

sec2θ=4xy(x+y)2tan2θ
=4xy(x+y)21
=(x+y)24xy(x+y)2
=(xyx+y)2
tan2θ+(xyx+y)2=0 (1)
For real θ,tan2θ0
and for real x,y;(xyx+y)20
So, each has to be individually zero to satisfy (1)

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