How do I calculate the phase &#x03D5;<!-- ϕ --> of sin &#x2061;<!-- ⁡ --> ( 4

Iyana Macdonald

Iyana Macdonald

Answered question

2022-04-10

How do I calculate the phase ϕ of sin ( 4 3 t ) relative to sin ( 3 t )? Also what would the angular frequency ω be?

Answer & Explanation

Makhi Lyons

Makhi Lyons

Beginner2022-04-11Added 15 answers

The sine function satisfies sin ( x + π ) = sin ( x ). Therefore,
sin ( 4 3 t ) = sin ( 3 t 4 + π )
And thus, the relative phase to sin ( 3 t ) is π 4 0.85
Tristan Meyers

Tristan Meyers

Beginner2022-04-12Added 5 answers

sin ( 4 3 t )
sin ( 3 t + 4 )
sin ( 3 t + π + 4 )
sin ( 3 t + ( π + 4 ) mod 2 π )
sin ( 3 t + 0.858 )

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