Solve 2 cos &#x2061;<!-- ⁡ --> x + 1 = 0 for x, where &#x03C0;<!-- π --> &#x2

Autumn Pham

Autumn Pham

Answered question

2022-05-14

Solve 2 cos x + 1 = 0 for x, where π x 3 π 2
A) 5 π 6
B) 7 π 6
C) 5 π 4
D) 4 π 3
2 cos x + 1 = 0
2 cos 2 x 1 + 1 = 0
2 cos 2 x = 0

Answer & Explanation

kazneni3tr2b

kazneni3tr2b

Beginner2022-05-15Added 17 answers

2 c o s ( x ) = 4 c o s 2 ( x / 2 ) 2 so equation becomes 4 c o s 2 ( x / 2 ) 1 = 0 thus c o s ( x / 2 ) = | 0.5 | now get the desired angle
Waylon Mcbride

Waylon Mcbride

Beginner2022-05-16Added 2 answers

cos x = 1 2 = cos π 3 = cos ( π π 3 )
as cos ( π ± u ) = cos u
x = 2 m π ± 2 π 3
Find suitable value of integer m so that
π x 3 π 2

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