Find the limit of b n </msub> = <munderover> &#x2211;<!-- ∑ --> <mrow clas

Kendrick Pierce

Kendrick Pierce

Answered question

2022-05-25

Find the limit of b n = i = 1 n 1 a i a i + 1

Answer & Explanation

Gloletheods6g

Gloletheods6g

Beginner2022-05-26Added 6 answers

Let
α = 3 5 2 , β = 3 + 5 2
be the zeros of the equation x 2 3 x + 1 = 0. Then by using α + β = 3 and α β = 1, we find that
a n + 1 α a n = α ( a n + 2 α a n + 1 ) .
From this, we get
a 2 α a 1 a i a i + 1 = α n 1 ( a i + 1 α a i ) a i a i + 1 = α i 1 a i α i a i + 1 .
So by telescoping,
b n = 1 a 2 α a 1 ( 1 a 1 α n a n + 1 ) .
Furthermore it is not hard to check that ( a i ) is increasing, hence a i 3 for all i Together this and |α|<1, we conclude
lim n b n = 1 ( a 2 α a 1 ) a 1 = 1 2 5 1 6 .

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