Tried playing with the formula of Conditional probability and some variations of combinatorics, beca

Emery Boone

Emery Boone

Answered question

2022-05-28

Tried playing with the formula of Conditional probability and some variations of combinatorics, because i know for sure that the 6th toss was head (we stop on the 3rd time we get head, and it's given to us that we stopped after 6 tosses). I know the answer is 0.4, but I cant unserstand how to get this answer, any help?

Answer & Explanation

stormsteghj

stormsteghj

Beginner2022-05-29Added 11 answers

1) following lulu's hint that 2 of the remaining 5 are heads we get that the number of ways of selecting two regardless of ordering is 5 × 4 2 = 10.
2) if we fix one of those as 1, there are 4 possibilities 4 10 = 0.4

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?