Show that f ( t

Sattelhofsk

Sattelhofsk

Answered question

2022-06-22

Show that f ( t ) = t 5 5 t + 1 has no repeated roots.

Answer & Explanation

Jake Mcpherson

Jake Mcpherson

Beginner2022-06-23Added 23 answers

f ( t ) = t 5 5 t + 1 f ( t ) = 5 t 4 5 , f ( 1 ) = 0 , f ( 1 ) = 0 , f ( i ) = 0 , f ( i ) = 0 but f ( 1 ) , f ( ± 1 ) , f ( ± i ) are non-zero. So there exist not even a root with multiplicity 2.

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